Download LearnGraduation Android App Now Get now!

SETS AND RELATION ||For Class 12 , JEE- Main & Advanced

sets and relations sets and relations jee mains questions pdf sets and relations pdf sets and relations formulas sets and relations class 12

SETS AND RELATIONS

sets and relations


∗  What is Set ?

Set :  A set is a collection of well defined objects which are distinct from each other

 Set are generally denoted by capital letters A, B, C, .... etc. and the elements of the set by a, b, c .... etc.

 If a is an element of a set A, then we write a ∊A and say a belongs to A.

 If a does not belong to A then we write a ∉ A,

e.g. The collection of first five prime natural numbers is a set containing the elements 2, 3, 5, 7, 11.


Ex. Which of the following are sets? Justify our answer.

(i) The collection of all months of a year beginning with the letter J.

(ii) The collection of ten most talented writers of India.

(iii) The collection of all boys in your class.

Sol. (i) The collection of all months of a year beginning with the letter J is a well defined collection of objects because  one can definitely identify a month that belongs to thisv collection. Hence, this collection is a set.

(ii) The collection of ten most talented writers of India is not a well defined collection because the criteria for  determining a writer’s talent may vary from person to person. Hence, this collection is not a set.

(iii) The collection of all boys in your class is a well defined collection because you can definitely identify a boy who belongs to this collection. Hence, this collection is a set.

Methods to Write a Set

(i) Roster Method or Tabular Method :  

In this method a set is described by listing elements, separated by commas and enclose then by curly brackets. Note that while writing the set in roster form, an element is not generally repeated e.g. the set of letters of word SCHOOL may be written as {S, C, H, O, L}.

Ex. Write the following sets in roster form:

(i) A = {x: x is an integer and –3 < x  <7}.

(ii) B = {x: x is a natural number less than 6}.

Sol. (i) A = {x: x is an integer and –3  <x < 7}

The elements of this set are –2, –1, 0, 1, 2, 3, 4, 5, and 6 only.

Therefore, the given set can be written in roster form as

A = {–2, –1, 0, 1, 2, 3, 4, 5, 6}

(ii) B = {x : x is a natural number less than 6}

The elements of this set are 1, 2, 3, 4, and 5 only.

Therefore, the given set can be written in roster form as

B = {1, 2, 3, 4, 5}

(iii) Set builder form (Property Method) : In this we write down a property or rule which gives us all the

 element of the set.

A = {x : P(x)} where P(x) is the property by which x A and colon ( : ) stands for ‘such that’

(iv) Symmetric difference of sets : 

It is denoted by A △ B and A △ B = (A – B) ⋃ (B – A) 

(v) Complement of a set : A' = {x : x A but x U} = U – A 

      e.g. U = {1, 2,........, 10}, A = {1, 2, 3, 4, 5} then A' = {6, 7, 8, 9, 10} 

(vi) Disjoint sets : If A ⋂ B = ф, then A, B are disjoint e.g. If A = {1, 2, 3}, B = {7, 8, 9} thenA ⋂ B = ф

Laws of Algebra of Sets (Properties of Sets)

(i) De-Morgan Laws :

 (A ⋃ B)' = A' ⋂ B' ; (A ⋂ B)' = A' ⋃ B'

(ii) A – (B ⋃ C) = (A – B) ⋂ (A – C) ; A – (B ⋂ C) = (A – B) ⋃ (A – C)

(iii) Distributive Laws :

 A ⋃ (B ⋂ C) = (A ⋃ B) ⋂ (A ⋃ C); A ⋂ (B ⋃ C) = (A ⋂ B) ⋃ (A ⋂ C)

(iv) Commutative Laws :

                                                   A ⋃ B = B ⋃ A ; A ⋂ B = B ⋂ A

(v) Associative Laws :

                                                   (A ⋂  B) ⋂  C = A ⋂  (B ⋂  C) ; (A ⋃B) ⋃C = A ⋃(B⋃ C)

(vi) Identity law :

                                                            A ⋂  U = A ; A ⋃ ф = A

(vii) Complement law :

                                                          A ⋂ A' = U, A ⋃  A' =  ф , (A')' = A

(viii) Idempotent law :

                                                          A ⋂ A = A, A ⋃ A = A

(ix) A ⋂ ф= ф ; A ⋂ U = A

     A ⋃  ф= A ; A ⋃  U = A

(x) A⋂ B ⊆ A ; A ⋂ B ⊆ B

(xi) A⊆ A ⋃ B ; B ⊆ A ⋃ B

(xii) A ⊆ B  ⇒ A ⋂  B = A

(xiii) A ⊆ B  ⇒ A ⋃  B = A


Ex.    Let A = {x : x R, |x| < 1] ; B = [x : x Є R, |x – 1| ≥ 1] and A ⋃ B = R – D, then the set D   is-

           (A) [x : 1 < x ≤ 2]       (B) [x : 1 ≤ x < 2]      (C) [x : 1 ≤  x ≤ 2]         (D) none of these

Sol.     A = [x : x ∊ R, –1 < x < 1]

         B = [ x : x  R : x – 1 ≤ –1 or x – 1 ≥ 1]   

               = [x : x R : x ≤ 0 or x ≥ 2]

            ∴ A ⋃ B = R – D

where D = [x : x ∈ R, 1 ≤ x < 2]

Thus (B) is the correct answer.

 

Venn Diagram  In  

 NEXT PAGE ≫

 

TOP  video from YOUTUBE



KEYWORDS ::

sets and relations                                                      sets and relations jee mains questions pdf
sets and relations pdf                                                sets and relations formulas
sets and relations class 12                                        sets and relations symbols
sets and relations all formulas                                  sets and relations questions and answers
sets and relations problems and solutions                sets and relations basics

Post a Comment